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Updated: 05/15/2008
- This is the simple example to list contents of any Directory. To do this we are going to define function DirDisply( ) which will read the current directory contents and display it as a list.
We first open current directory by $TrackDir=opendir(&".&");
The opendir function returns a directory handle resource on success, or FALSE on failure.
Syntax is:
opendir ( string path [, resource context] )
Where:
Path - The directory path that is to be opened Context - For a description of the context parameter, refer to the streams section of the php manual.
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